n^2/7=448

Solution for n^2/7=448 equation:

n^2/7=448

We move all terms to the left:

n^2/7-(448)=0

We multiply all the terms by the denominator


n^2-448*7=0

We add all the numbers together, and all the variables

n^2-3136=0

a = 1; b = 0; c = -3136;
Δ = b2-4ac
Δ = 02-4·1·(-3136)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-112}{2*1}=\frac{-112}{2}
=-56
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+112}{2*1}=\frac{112}{2}
=56
$